Line `L_1` is parallel to the line `L_2`. Slope of `L_1` is `9`. Also `L_3`, is parallel to `L_4`. Slope of `L_4` is `1/-25` All these lines touch the ellipse`x^2/25+y^2/9=1`. Find the area of the parllelogram formed by these lines.

The area of triangle formed by the lines l_1 and l_2 and the x-axis is:

Let L be a common tangent line to the curves 4x^2+9y^2=36 and (2x)^2+(2y)^2=31 . Then the square of the slope of the line L is "________"

Find the slope of line l which is parallel to X -axis . Also , find the slope of line n which is parallel to Y-axis .

Line L is perpendicular to the line with equation y= 3x – 5, contains the point (1,4). The x-intercept of L is

A straight line L is perpendicular to the line 5x-y=1. The area of the triangle formed by line L, and the coordinate axes is 5. Find the equation of line L.

A line L passeds through the points (1,1) and (2,0) and another line L' passes through ((1)/(2), 0) and perpendicular to L. Then the area of the triangle formed by the lines L, L' and Y-axis is

A point P is 3units away from line L_1= 3x + 4y +5=0 and 4 units away from the line L_2 = 8x-by +9=0, The reflection of P on L_1, is P_1 the reflection of P_1 on L_2, is P_2 the reflection of P_3, on L_2, is P_4, Then the area (in sq. units) of figure formed by joining P_1P_2P_3, and P_4, is-