Home
Class 11
PHYSICS
A block of mass m=2kg is placed in equil...

A block of mass `m=2kg` is placed in equilibrium on a moving plank accelerating with `a=4m//s^(2)` . If coefficient of friction between plank and block `mu=0.2` . The friction force acting on theblock is:

Promotional Banner

Similar Questions

Explore conceptually related problems

A block of mass m=2kg is placed in equilibrium on a moving plank accelerating with a=1m//s^(2) . If coefficient of friction between plank and block mu=0.2 . The friction force acting on theblock is:

If coefficient of friction between both the block is mu- (1)/(2) . Find friction force acting between both block.

A block of mass 1 kg is placed on a truck which accelerates with acceleration 5ms^(-2) . The coefficient of static friction between the block and truck is 0.6. The frictional force acting on the block is

In the arrangement shown in figure coefficient of friction between 5kg block and incline plane is mu=0.5 . Friction force acting on the 5kg block is

A block of mass m is placed in equilibrium on a moving plank. The maximum horizontal acceleration of the plank for mu=0.2 is:

In the arrangement shown in figure, coefficient of friction between the two blocks is mu=1//2 . The force of friction acting between

In the figure shown a ring of mass M and a block of mass m are in equilibrium. The string is light and pulley P does not offer any friction and coefficient of friction between pole and M is mu. The frictional force offered by the pole to M is

A block of mass m=4kg is placed oner a rough inclined plane as shown in figure. The coefficient of friction between the block and the plane is mu=0.5 . A force F=10N is applied on the block at an angle of 30^(@) .

A small block of mass 1kg is placed over a plank of mass 2kg. The length of the plank is 2 m. coefficient of friction between the block and the plnak is 0.5 and the ground over which plank in placed is smooth. A constant force F=30N is applied on the plank in horizontal direction. the time after which the block will separte from the plank is (g=10m//s^(2))

A block of mass M is sliding down the plane. Coefficient of static friction is mu_(s) and kinetic friction is mu_(k) . Then friction force acting on the block is :