Locus of the image of a point A(0,0) in the line (2a+b)x+(3a-2b)y+(b-5a)=0 is (where a and b are parameters).

If the locus of the image of the point (lambda^(2), 2lambda) in the line mirror x-y+1=0 (where lambda is a parameter) is (x-a)^(2)=b(y-c) where a, b , c in I , then the value of ((a+b)/(c+b)) is equal to

Locus of the image of the point (1,1) in the line (5x-2y-7)+lambda(2x-3y+6)=0 (lambda in R'), is

Locus of the image of the point (1,1) in the line (5x-2y-7)+lambda(2x-3y+6)=0lambda in R, is

For all the values of 'a' and 'b',the lines (a+2b)x+(a-b)y+(a+5b)=0 passes through the point

The locus of the point x=a+lambda^(2),y=b-lambda where lambda is a parameter is

Two point (b+3,b+k) and (2,b) are on the line x-2y+9=0 find k