The diameter of the largest circle with center (1,0) which is inscribed in the ellipse `x^(2)+4y^(2)=16` is k.Then integral part of k is

Find the equation of the largest circle with centre (1,0) that can be inscribed in the ellipse x^(2)+4y^(2)=16

Find the equation of the largest circle with centre (1,0) that can be inscribed in the ellipse x^(2)+4y^(2)=16

If A be the area of the largest circle with centre (1, 0) that can be inscribed in the ellipse x^2 + 4y^2 = 16 , then 945/pi A = .

If a circle is inscribed in the ellipse x^(2)+4y^(2)=4, then range of radius of circle is

The area of the rectangle of maximum area inscribed in the ellipse (x^(2))/(25)+(y^(2))/(16)=1 is

The area of the rectangle of maximum area inscribed in the ellipse (x^(2))/(25)+(y^(2))/(16)=1 is

If 4x-3y+k=0 touches the ellipse 5x^(2)+9y^(2)=45 , then k is equal to

The area of the parallelogram inscribed in the ellipse x^(2)/a^(2)+y^(2)/b^(2)=1 , whose diaonals are the conjugate diameters of the ellipse is given by

The line 3x+5y=k touches the ellipse 16x^(2)+25y^(2)=400 ,if k is