A toroid is wound over a circular core. Radius of each turn is r and radius of toroid is R(>>r). The Coefficient of self - inductance of the toroid is given by

A toroid is wound over a circular core. Radius of each turn is r and radius of toroid is R (gt gt r) . The coefficient of self-inductance of the toroid is given by

The self inductance of a toroid is :-

A circular coil of radius 5 cm has 500 turns of a wire. The approximate value of the coefficient of self-induction of the coil will be

A toroid of 1000 turns has an average radius of 10 cm and area of cross section 15 cm^(2) . Calculate the self-inductance of the toroid.

A coil of radius r is placed at the centre of R>>r and coils are in same plane.The coefficient of mutual inductance between the coil is

Two coils are made of copper wires of same length in the first coil the number turns is 3n and radius is r. In the second coil number of turns is n and radius is 3r the ratio of self inductances of the coils will be :-

A toroidal solenoid with an air core has an average radius of 15 cm, area of cross-section 12 cm^(2) and 1200 turns. Obtain the self inductance of the toroid. Ignore field variations across the cross-section of the toroid. (b) A second coil of 300 turns is wound closely on the toroid above. If the current in the primary coil is increased from zero to 2.0 A in 0.05 s, obtain the induced e.m.f. in the second coil.

[" A small circular coil of radius " "r" and having "n' turns carries a current "7" .The coefficient of self-induction of the coil is "],[[" (A) "mu_(0)pi nr/2],[" (B) ",mu_(0)pi nr],[" (C) ",mu_(o)pi n^(2)r/2],[" (D) ",mu_(o)pi nr^(2)/2]]

A circular coil of wire of radius r has 600 turns and self inductance 108mH .The self inductance of a coil with same radius and 500 turns is

A closely wound coil of 100 turns and area of cross-section 1cm^(3) has a coefficient of self-induction 1 mH . The magnetic induction in the centre of the core of the coil when a current of 2A flows in it, will be