`min[(x_1-x^2)^2+(3+sqrt(1-x1 2)-sqrt(4x_2))],AAx_1,x_2 in R ,` is `4sqrt(5)+1` (b) `3-2sqrt(2)` `sqrt(5)+1` (d) `sqrt(5)-1`

min[(x_(1)-x_(2))^(2)+(3+sqrt(1-x_(1)^(2))-sqrt(4x_(2)))],AA x_(1),x_(2)in R is (a)4sqrt(5)+1 (b) 3-2sqrt(2)(c)sqrt(5)+1(d)sqrt(5)-1

If x=sqrt(5)+2, then x-(1)/(x) equals 2sqrt(5)(b)4 (c) 2 (d) sqrt(5)

(12)/(3+sqrt(5)+2sqrt(2)) is equal to 1-sqrt(5)+sqrt(2)+sqrt(10) (b) 1+sqrt(5)+sqrt(2)-sqrt(10) (c) 1+sqrt(5)-sqrt(2)+sqrt(10) (d) 1-sqrt(5)-sqrt(2)+sqrt(10)

If x=5+2sqrt(6), then (x-1)/(sqrt(x)) is equal to a.sqrt(2) b.sqrt(3)c.2sqrt(2)d.2sqrt(3)

int_(-1)^((1)/(2))(e^(x)(2-x^(2))dx)/((1-x)sqrt(1-x^(2))) is equal to (sqrt(e))/(2)(sqrt(3)+1) (b) (sqrt(3e))/(2)sqrt(3e)(d)sqrt((e)/(3))

If (sqrt(1+x^(2))+sqrt(1-x^(2)))/(sqrt(1+x^(2))-sqrt(1-x^(2)))=3 then x=1)sqrt((2)/(3)2)sqrt((1)/(3))3)sqrt((2)/(5))sqrt((3)/(5))

int_(1)^(5)(sqrt(x+2sqrt(x-1))+sqrt(x-2sqrt(x-1)))dx =

int(xdx)/(sqrt((1+x^2)+sqrt((1+x^2)^3)))= (a) 1/2ln(1+sqrt(1+x^2))+c (b) 2sqrt(1+sqrt(1+x^2))+c (c) 2(1+sqrt(1+x^2))+c (d) 4sqrt(1+sqrt(1+x^2))+c

[ If N=(sqrt(sqrt(5)+2)+sqrt(sqrt(5)-2))/(sqrt(sqrt(5)+1))-sqrt(3-2sqrt(2)) then N equals [ (A) 1, (B) 2sqrt(2)-1 (C) (sqrt(5))/(2), (D) (2)/(sqrt(sqrt(5)+1))]]

x=sqrt(1+2sqrt(1+3sqrt(1+4sqrt(1+...))))