A ball is projected from ground and it crosses point A and B which are on same level after 3 sec and 5 sec of projection. If ball is at half of maximum height at time `t_(1)`& `t_(2)`, then find `(t_(1) + t_(2))/5`.

A ball is projected from ground and it crosses point A and B which are on same level after 3 sec and 5 sec of projection. If ball is at half of maximum height at time t_(1) & t_(2) ,then find (t_(1)+t_(2))/2 .

A ball projected from ground vertically upward is at same height at time t_(1) and t_(2) . The speed of projection of ball is [Neglect the effect of air resistance ]

A ball is projected at some angle with ground such that it is at a particular height two times at t = 4s and t = 6s . Find the maximum height of the projecticle during the motion.

A particle is projected with speed u at angle theta with horizontal from ground . If it is at same height from ground at time t_(1) and t_(2) , then its average velocity in time interval t_(1) to t_(2) is

A projectille can have the same range R for two angles of projection. If t_(1) and t_(2) be the time of flight in the two cases, then find the relation between t_(1), t_(2) and R .

Two particles projected form the same point with same speed u at angles of projection alpha and beta strike the horizontal ground at the same point. If h_1 and h_2 are the maximum heights attained by the projectile, R is the range for both and t_1 and t_2 are their times of flights, respectively, then

A ball is projected vertically upwards. Air resistance and variation in g may be neglected. The ball rises to its maximum height H in a time T, the height being h after a time t : (1) The graph of kinetic energy E_(k) of the ball against height h is shown in figure 1 (2) The graph of height h against time t is shown in figure 2 (3) The graph of gravitational energy E_(k) of the ball against height h is shown in figure 3 (1) Two particles move on a circular path ( one just inside and the other just outside) with angular velocities ro and 5 omega starting from the same point. Then :

A charged ball of mass m and charge q is projected from the ground with an initail velocity u and angle of projection theta at the time of projection vertically upward electric field E is switched on. When it reaches the maximum height electric filed is switched off and a horizontal electric feild of same magnitude E is switched on. Then answer the following question (Assume mg> qE) Q If the time of flight to the maximum height is t_1 and the time of flight maximum height to the ground is t_2 then

For a given velocity, a projectile has the same range R for two angles of projection. If t_(1) and t_(2) are the time of flight in the two cases, then t_(1) = t_(2) is equal to