In a certain system of absolute units the acceleration produced by gravity in a body falling freely is denoted by `3`, the kinetic energy of a `272.1 kg` shot moving with velocity `448` metres per second is denoted by `100`, and its momentum by 10.
The unit of length is

In a certain system of absolute units the acceleration produced by gravity in a body falling freely is denoted by 3 , the kinetic energy of a 272.1 kg shot moving with velocity 448 metres per second is denoted by 100 , and its momentum by 10. the unit of mass is

In a certain system of absoulte units the acceleration produced by gravity in a body falling freely is denoted by 5, the kinetic energy of a 500 kg shot moving with velocity 400 metres per second is denoted by 2000 & its momentum by 100 The unit of length is :-

n a certain system of absoulte units the acceleration produced by gravity in a body falling freely is denoted by 5, the kinetic energy of a 500 kg shot moving with velocity 400 metres per second is denoted by 2000 & its momentum by 100 The unit of time is :-

n a certain system of absoulte units the acceleration produced by gravity in a body falling freely is denoted by 5, the kinetic energy of a 500 kg shot moving with velocity 400 metres per second is denoted by 2000 & its momentum by 100 The unit of mass is :-

Calculate the kinetic energy of a body of mass 2 kg moving with a velocity of 0.1 meter per second.

A body of masss 1kg is allowed to fall freely under gravity. Find the mimimum and kinetic energy of the body 5 second after it starts falling. Take g= 10 ms^(-2)

Two identical beads, each of m=100g , are connected by an inextensible massless string, which can slide along the two arms AC and BC of a rigid smooth wire frame in a vertical plane. If the system is released from rest, the kinetic energy of the first bead when the second bead has moved down by a distance of 0.1m is xxx10^-3J . Find the value of x(g=10ms^-2) (shown situation is after movement of 0.1m ).

1 joule of energy is to be converted into new system of units in which length is measured in 10 metre, mass in 10 kg and time in 1 minute. The numerical value of 1 J in the new system is :-

In ancient time, deffernt system of units was following in which unit of mass was " ser ", unit of length was " gaj " & unit of time was " kall " 1ser=900 gm , 1gaj=90cm , 1 kaal=3hr . A ball of mass 9kg is moving with velocity 10 m//s . Then its momentum ( mv ) in ancient system will be :-