A small stone is dropped from top of a long tower.The ratio of distance travelled by the particle between t=5 s to t=10s and t=15s to t=20s is ?

The speed-time graph of a particle moving along a fixed direction as shown in the figure. The distance traversed by the particle between t = 0 s to t = 10 s is

The distance travelled (in meters) by the particle from time to t = 0 to t = 1s will be –

The position of a particle is given by x=2(t-t^(2)) where t is expressed in seconds and x is in metre. The total distance travelled by the paticle between t=0 to t=1s is

If S=16+(192) t-t^(3) , then distance travelled by the particle before coming to rest is

The instantaneous velocity of a particle moving in a straight line is given as v = alpha t + beta t^2 , where alpha and beta are constants. The distance travelled by the particle between 1s and 2s is :

The speed-time graph of a particle moving along a fixed direction is shown in figure. Obtain the distance traversed by the particle between (a)t=0s to 10s(b)t=2s to 6s What is the average speed of the particle over the intervals in a and b?

The position (in meters) of a particle moving on the x-axis is given by: x=2+9t +3t^(2) -t^(3) , where t is time in seconds . The distance travelled by the particle between t= 1s and t= 4s is m.

If the distance s travelled by a particle in time t is s=a sin t +b cos 2t , then the acceleration at t=0 is

Velocity time equation of a particle moving in a straight line is v=2t-4 for tle2s and v=4-2t for tgt2 .The distance travelled by the particle in the time interval from t=0 to t=4s is (Here t is in second and v in m/s)

The position versus time graph of a particle moving along a straight line is shown. What is the total distance travelled by the particle from t=0s to t=10s?