(−4,1),(6,1) are the vertices of an ellipse and one of the foci lies on x−2y=2 then the eccentricity is

If F_1 (-3, 4) and F_2 (2, 5) are the foci of an ellipse passing through the origin, then the eccentricity of the ellipse is

A parabola is drawn with focus at one of the foci of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1. If the latus rectum of the ellipse and that of the parabola are same,then the eccentricity of the ellipse is 1-(1)/(sqrt(2)) (b) 2sqrt(2)-2sqrt(2)-1( d) none of these

The equation of the ellipse with foci (pm 2, 0) and eccentricity =1/2 is

if vertices of an ellipse are (-4,1),(6,1) and x-2y=2 is focal chord then the equation of the ellipse is

The equation of the ellipse whose foci are (pm2,0) and eccentricity is 1/2 is

The equation to the ellipse whose foci are (pm2,0) and eccentricity 1/2 is

Find the lengths of the major and minor axes, coordinates of the vertices and the foci, the eccentricity and length of the latus rectum of the ellipse: x^(2)/4+y^(2)/36 = 1.