Points A(0,6,8) and B(15,20,0) are given. Let `P(alpha,0,0)` is a point on x - axis such that `PA+PB` is minimum Then value of `alpha` is

If A (3,1) and B (-5,7) are any two given points, If P is a point one the line y = x such that PA + PB is minimum then P is

A(-3,2),B(2,5) be two points if the point P(0,k) lies on y- axis such that |PA-PB| is maximum. Then (k-1)/(5)=

Consider the points A(0,1) and B(2,0) and P be a point on the line 4x+3y+9=0 .Coordinates of P such that |PA-PB| is maximum are

Consider two points A=(-3,0) and B=(0,4). If a point P on the line 2x-3y-12=0 is such that |PA-PB| is maximum,then P is

Find a point P on the line 3x+2y+10=0 such that |PA - PB| is minimum where A is (4,2) and B is (2,4)

A student of IIN starts from a point P(-3,4) and reaches point Q(0,1) via R(alpha,0) such that perimeter ofthe triangle PQR is minimum, then the value of 10| alpha| is-

A(-9,0),B(-1,0) are two points.If P is a point such that PA:PB=3:1, then the locus of P is

Let A(0,-4) and B(0,4) be two fixed points. Find the locus of a point P which moves so that PA+PB=12 .