`PH_(3)` and `BF_(3)` form an adduct readily because they form

NH_(3)and BF_(3) from adduct readily because they from

BF_(3) is.

BF_3 and NH_3 combine readily because of the formation of

Statement-1 : PH_(3) and BF_(3) both are electron deficient molecule. Statement-2 : P-H bond length are identical in PH_(3) and all B-F bond length are also identical in BF_(3) .

PH_(3) can be formed in

SbF_(5) reacts with XeF_(4) to form an adduct. The shapes of cation and anion in the adduct are respectively :