For neutralising exactly "60ml" of "2N" base "120ml" of an acid is required, the normality of the acid is

0.1914 g of an organic acid is dissolved in about 20 mL of water. 25 mL of 0.12 N NaOH is required for complete neutralization of the acid solution. The equivalent mass of the acid is

If 20 mL of 0.4 N NaOH solution completely neutralises 40 mL of a dibasic acid, the molarity of the acid solution is :

2.52 g of oxalic acid dehydrate was dissolved in 100 ml of water, 10 mL of this solution was diluted to 500 mL. The normality of the final solution and the amount of oxalic acid (mg/mL) in the solution are respectively-

Volume required for neutralization: What volume of 0.100 N HCl solution is required to netralize completely 50.0 mL of a 0.150 N solution of Ba(OH)_(2) ? Strategy: We know three of the four variables in the relationship. mL_(acid)xxN_(acid)=mL_(base)xxN_(base) and so we solve for mL_(acid)

A solution (5 mL) of an acid X is completely neutralized by y mL of 1M NaOH. The same volume (y ML) of 1M NaOH is required to neutralize 10 mL of 0.6 M of H_(2)SO_(4) completely. The normality (N) of the acid X is