Let AandB be acute angles such that `sinA=sin^2B` and `2cos^2A=3cos^2B`. Then A equal to

Let AandB be acute angles such that sin A=sin^(2)B and 2cos^(2)A=3cos^(2)B. Then A equal to

If A and B are acute angles such that sinA=sin^(2)B,2cos^(2)A=3cos^(2)B then B equal to

If sinA=sin^2B and 2cos^2A=3cos^2B then the triangle ABC is

If A and B are positive acute angles such that sin (A - B) =1/2 and cos (A + B) = 1/2 , then A and B are given by

If A and B are acute angles such that sin A =cos B , prove that (A+B)=90^@ .

Prove that sin(A+B)sin(A-B)=cos^2B-cos^2A

In sinA=sinB and cos A=cos B , then prove that sin(A-B)/(2)=0