By eliminating the parameters A and `alpha` in `x=A cos(pt+alpha)` ,the differential equation obtained is

By eliminating parameters A and alpha in x=A cos(pt+alpha) the differential equation obtained is -

int(cos alpha)/(sin x cos(x-alpha))dx=

Let y = (a sin x+ (b +c) cos x ) e ^(x+d), where a,b,c and d are parameters represent a family of curves, then differential equation for the given family of curves is given by y'' -alpha y'+betay=0, then alpha+ beta =

Eliminate alpha , if x = r cos alpha , y = r sin alpha .

If 0 le alpha le 2pi and int_(0)^(alpha)cos x dx = cos 2alpha , the : alpha =

Write the differential equation obtained by eliminating the arbitrary constant C in the equation representing the family of curves xy=C cos x

Show that the equation of a line passing through the point (a cos^(3)alpha,a sin^(3)alpha) and perpendicular to the line x sec alpha+y cos ec alpha=a is x cos alpha-sin alpha=a cos2 alpha

(cos2x-cos2 alpha)/(cos x-cos alpha)

(cos2x-cos2 alpha)/(cos x-cos alpha)

The differential equation of minimum order by eliminating the arbitrary constants A and C in the equation y = A [sin (x + C) + cos (x + C)] is :