What is the energy required for separation of an `O^(16)` nucleus into four identical particles? (Nuclear masses: `O^(16)=15.9944u`,`He^(4)`=4.0026u 1 amu= 931.5MeV

Making use of the table of atomic masses given above find the energy required for the separation of an ._(8)^(16)O nucleus into 4 identical particle

Find the energy required to split ._(8)^(16)O nucleus into for alpha - particles. The mass of alpha - particle is 4.002603u and that of oxygen is 15.994915 u .

What would be the energy required to dissociate completely 1 g of Ca-40 into its constituent, particles? Given: Mass of proton =1.00866 am u , Mass of neutron =1.00866 am u , Mass of Ca-40 =39.97454 am u , (Take 1 am u =931 MeV ).

What is the minimum energy that is required to break a nucleus of ""^(12)C (of mass 11.996 71 u) into three nuclei of ""^(4)He (of mass 4.001 51 u each)?

Find the mean binding energy per one nucleon in 0^(16) nucleus in MeV.Given m(O^(16)) =15.9994amu, m(H^(1)) =1.007823amum m(n^(1)) =1.008665amu

Assuming that in a star, three alpha particle join in a single fusion reaction to form ._(6)C^(12) nucleus. Calculate the energy released in this reaction. Given mass of ._(2)He^(4) is 4.002604 a.m.u. and that of ._(6)C^(12) is 12 a.m.u. Take 1a.m.u. =931MeV.

Find the binding energy and the binding energy pernucleon of the nucleus of ._(8)^(16)O . Given atomic mass of ._(8)^(16)O(m)=15.994915 amu, mass of proton (m_(p))=1.007823 amu, mass of a neutron (m_(n))=1.008665 amu and 1 amu =931.5 MeV.

Helium nuclei combine to form an oxygen nucleus. The energy released in the reaction is if m_(O)=15.9994 "amu" and m_(He)=4.0026 "amu"

Helium nuclei combines to form an oxygen nucleus. The energy released per nucleon of oxygen nucleus is if m_(0)=15.834 amu and m_(He)=4.0026 amu