If `4costheta*cos(120+theta)*cos(120-theta)=1/2` then `theta=`

If 4cos theta*cos(120+theta)*cos(120-theta)=(1)/(2) then theta=

If 4 cos theta.cos(120^(@)+theta).cos(120^(@)-theta)=1//2 then theta =

cos^2theta+cos^2(120^@+theta)+cos^2(120^@-theta)=.....

Solve costheta+cos3theta-2cos2theta=0 .

costheta.cos2theta.cos3theta=1/4

For any angle theta , costheta+cos(120^@+theta)+cos(120^@-theta)=........

cos theta + cos (120^(@) + theta ) + cos (120^(@) - theta )=

Statement I: If x cos theta=y cos(120^(@)+theta)=z cos(theta+240^(@)) then xy+yz+zx=1 Statement II: cos alpha+cos(120^(@)+alpha)+cos(120^(@)alpha)=0 Which of the above statements is correct