Given that `A(1,-1)` and locus of B is `x^2 + y^2 = 16`.1f `P` divides `AB` in the ratio `3: 2` then locus of `P` is

A=(2,-1) locus of B is x^(2)+y^(2)=25. If P divides AB in the ratio 1:2 then locus of P is

A variable line through the point (1/5,1/5) cuts the coordinate axes in the points A and B. If the point P divides AB internally in the ratio 3: 1, then the locus of P is :

A variable line through the point (6/5, 6/5) cuts the coordinates axes in the point A and B . If the point P divides AB internally in the ratio 2:1 , show that the equation to the locus of P is :

Let P be a point on x^2 = 4y . The segment joining A (0,-1) and P is divided by point Q in the ratio 1:2, then locus of point Q is

Let P be a point on x^2 = 4y . The segment joining A (0,-1) and P is divided by point Q in the ratio 1:2, then locus of point Q is

A(2, 1) and B(1, 2) are two points. If P is a point such that PA : PB = 2:1 , then the locus of P is

A line AB meets X-axis at A and Y-axis at B. P(4, -1) divides AB in the ratio 1:2. Find the co-ordinates of A and B.

A line AB meets X-axis at A and Y-axis at B. P(4, -1) divides AB in the ratio 1:2. Find the Coordinates of A and B

Let the foci of the ellipse (x^(2))/(9) + y^(2) = 1 subtend a right angle at a point P . Then the locus of P is _