Coper metal can reduce `Fe^(2+)` in acidic medium.

Copper metal reduces Fe^(2+) in an acid medium.

A given amount of Fe^(2+) is oxidised by x mol of MnO_4^– in acidic medium. Calculate mol of Cr_2O_7^(2–) required same amount of Fe^(2+) in acidic medium

A given amount of Fe^(2+) is oxidized by x mol of MnO_4^(-) in acidic medium. The number of mole of Cr_2O_7^(2-) required to oxidize the same amount of Fe^(2+) in acidic medium is

Assertion : In acid solution, permanganate is reduced to Mn^(2+) by an excess of reducing agent. Reason : MnO_(4)^(-) reduced in Mn^(2+) in acidic medium and the product in the presence of an excess of permanganate is MnO_(2) .

Potassium permanganate is used as a ul"reducing agent" in acidic medium.

If equal volumes of 0.1 M KMnO_(4) and 0.1 M K_(2)Cr_(2)O_(7) solutions are allowed to oxidise Fe^(2+) to Fe^(3+) in acidic medium, then Fe^(2+) oxidised will be: