`4y^(2) - 5y + 1` is a ……………..

(2y + 5) / (y + 4) = 1

Subtract : 5y^(4) - 3y^(3) + 2y^(2) + y - 1 from 4y^(4) - 2y^(3) - 6y^(2) - y + 5

int_(0)^(4)((y^(2)-4y+5)sin(y-2)dy)/([2y^(2)-8y+1]) is equal to

int_(0)^(4)((y^(2)-4y+5)sin(y-2)dy)/([2y^(2)-8y+1]) is equal to

int_(0)^(4)((y^(2)-4y+5)sin(y-2)dy)/([2y^(2)-8y+1]) is equal to

Transform the expression x^(2) - xy+y^(2)+4x-5y-1 into the form Ax^(2)+By^(2)+C by suitable transformations.

Acute angle through which co-ordinate axes are rotated in order to remove xy term in 5x^(2)+2xy+3y^(2)+4x+5y+1=0 is (pi)/(n) where (2n) equals

Add : 4y (3y^2 + 5y – 7) and 2 (y^3 – 4y^2 + 5)

Divide: (2y^(2) - 3y^(3) + 5y-4) // (y-1)