Solve `35x^(3)y^(2)div 7x^(2)y^(2)`

Answer

To solve the expression \( \frac{35x^3y^2}{7x^2y^2} \), we can follow these steps:

### Step 1: Simplify the coefficients
First, we simplify the numerical coefficients. We have \( 35 \) in the numerator and \( 7 \) in the denominator.

\[ \frac{35}{7} = 5 \]

### Step 2: Simplify the \( x \) terms
Next, we simplify the \( x \) terms. We have \( x^3 \) in the numerator and \( x^2 \) in the denominator.

Using the property of exponents \( \frac{x^a}{x^b} = x^{a-b} \):

\[ \frac{x^3}{x^2} = x^{3-2} = x^1 = x \]

### Step 3: Simplify the \( y \) terms
Now, we simplify the \( y \) terms. We have \( y^2 \) in both the numerator and the denominator.

\[ \frac{y^2}{y^2} = 1 \]

### Step 4: Combine the results
Now we combine all the simplified parts together:

\[ 5 \cdot x \cdot 1 = 5x \]

### Final Answer
Thus, the simplified form of \( \frac{35x^3y^2}{7x^2y^2} \) is:

\[ \boxed{5x} \]