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The set of values of p for which t...

The set of values of p for which the expression `x^(2)` −2px+3p+4 is negative for at least one real x is

A

a. `p lt 1`

B

b. `p=0`

C

c. (−∞,−1) U (4,∞)

D

d. `p in (-(1)/(2),(1)/(2))`

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The correct Answer is:
To solve the problem, we need to determine the set of values of \( p \) for which the expression \( x^2 - 2px + 3p + 4 \) is negative for at least one real \( x \). This can be achieved by analyzing the discriminant of the quadratic expression. ### Step-by-Step Solution: 1. **Identify the Quadratic Coefficients**: The given expression is \( x^2 - 2px + (3p + 4) \). Here, we identify: - \( a = 1 \) - \( b = -2p \) - \( c = 3p + 4 \) 2. **Determine the Condition for Negativity**: For the quadratic expression to be negative for at least one real \( x \), the discriminant \( D \) must be greater than 0: \[ D = b^2 - 4ac > 0 \] 3. **Calculate the Discriminant**: Substitute the values of \( a \), \( b \), and \( c \) into the discriminant formula: \[ D = (-2p)^2 - 4 \cdot 1 \cdot (3p + 4) \] Simplifying this gives: \[ D = 4p^2 - 4(3p + 4) \] \[ D = 4p^2 - 12p - 16 \] 4. **Set Up the Inequality**: We need to solve the inequality: \[ 4p^2 - 12p - 16 > 0 \] Dividing the entire inequality by 4 simplifies it: \[ p^2 - 3p - 4 > 0 \] 5. **Factor the Quadratic**: We can factor the quadratic expression: \[ (p - 4)(p + 1) > 0 \] 6. **Determine the Intervals**: To find where the product is greater than zero, we analyze the critical points \( p = -1 \) and \( p = 4 \). We test the intervals: - For \( p < -1 \): Choose \( p = -2 \) → \( (-2 - 4)(-2 + 1) = (-6)(-1) > 0 \) (True) - For \( -1 < p < 4 \): Choose \( p = 0 \) → \( (0 - 4)(0 + 1) = (-4)(1) < 0 \) (False) - For \( p > 4 \): Choose \( p = 5 \) → \( (5 - 4)(5 + 1) = (1)(6) > 0 \) (True) 7. **Conclusion**: The solution to the inequality \( (p - 4)(p + 1) > 0 \) gives us the intervals: \[ p \in (-\infty, -1) \cup (4, \infty) \] ### Final Answer: The set of values of \( p \) for which the expression \( x^2 - 2px + 3p + 4 \) is negative for at least one real \( x \) is: \[ (-\infty, -1) \cup (4, \infty) \]
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