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The domain of y=(1)/(sqrt(|x|-x)) is :...

The domain of `y=(1)/(sqrt(|x|-x))` is :

A

`[0,oo)`

B

`(0,oo)`

C

`(-oo,0)`

D

`(-oo,0]`

Text Solution

AI Generated Solution

The correct Answer is:
To find the domain of the function \( y = \frac{1}{\sqrt{|x| - x}} \), we need to ensure that the expression inside the square root is non-negative and that the denominator is not equal to zero. ### Step-by-Step Solution: 1. **Identify the conditions for the square root**: The expression inside the square root must be greater than or equal to zero: \[ |x| - x \geq 0 \] 2. **Analyze the absolute value**: The absolute value function \( |x| \) behaves differently depending on whether \( x \) is non-negative or negative: - If \( x \geq 0 \), then \( |x| = x \). - If \( x < 0 \), then \( |x| = -x \). 3. **Case 1: \( x \geq 0 \)**: If \( x \geq 0 \): \[ |x| - x = x - x = 0 \] This does not satisfy \( |x| - x > 0 \) (it equals zero), so we discard this case. 4. **Case 2: \( x < 0 \)**: If \( x < 0 \): \[ |x| - x = -x - x = -2x \] We need to find when this is greater than zero: \[ -2x > 0 \implies x < 0 \] This condition is satisfied for all \( x < 0 \). 5. **Check the condition for the denominator**: The denominator must not be equal to zero: \[ |x| - x \neq 0 \] From our previous analysis, we see that \( |x| - x = 0 \) only when \( x = 0 \) (which we already excluded) and is not an issue for \( x < 0 \). 6. **Conclusion**: The only values of \( x \) that satisfy both conditions (the expression inside the square root being greater than zero and the denominator not being zero) are: \[ x < 0 \] Therefore, the domain of the function is: \[ (-\infty, 0) \] ### Final Answer: The domain of \( y = \frac{1}{\sqrt{|x| - x}} \) is \( (-\infty, 0) \).
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