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How many times does the graph of y=x^(3)...

How many times does the graph of `y=x^(3)-3x^(2)-x+3` intersects the x - axis :

A

1

B

2

C

3

D

none of these

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The correct Answer is:
To determine how many times the graph of the function \( y = x^3 - 3x^2 - x + 3 \) intersects the x-axis, we need to find the roots of the equation \( y = 0 \). This means we need to solve the polynomial equation: \[ x^3 - 3x^2 - x + 3 = 0 \] ### Step 1: Find a root of the polynomial We can start by testing some simple values of \( x \) to see if they yield \( y = 0 \). Let's try \( x = 1 \): \[ y = 1^3 - 3(1^2) - 1 + 3 = 1 - 3 - 1 + 3 = 0 \] Since \( y = 0 \) when \( x = 1 \), we have found one root: \( x = 1 \). ### Step 2: Factor the polynomial Since \( x = 1 \) is a root, we can factor the polynomial using \( (x - 1) \). We will perform polynomial long division to divide \( x^3 - 3x^2 - x + 3 \) by \( (x - 1) \). 1. Divide \( x^3 \) by \( x \) to get \( x^2 \). 2. Multiply \( (x - 1) \) by \( x^2 \) to get \( x^3 - x^2 \). 3. Subtract \( (x^3 - x^2) \) from \( (x^3 - 3x^2) \) to get \( -2x^2 \). 4. Bring down the next term, resulting in \( -2x^2 - x + 3 \). 5. Divide \( -2x^2 \) by \( x \) to get \( -2x \). 6. Multiply \( (x - 1) \) by \( -2x \) to get \( -2x^2 + 2x \). 7. Subtract \( (-2x^2 + 2x) \) from \( (-2x^2 - x) \) to get \( -3x + 3 \). 8. Bring down the next term, resulting in \( -3x + 3 \). 9. Divide \( -3x \) by \( x \) to get \( -3 \). 10. Multiply \( (x - 1) \) by \( -3 \) to get \( -3x + 3 \). 11. Subtract to get \( 0 \). Thus, we have: \[ x^3 - 3x^2 - x + 3 = (x - 1)(x^2 - 2x - 3) \] ### Step 3: Factor the quadratic Next, we need to factor the quadratic \( x^2 - 2x - 3 \). We can factor it as follows: \[ x^2 - 2x - 3 = (x - 3)(x + 1) \] ### Step 4: Write the complete factorization Now we can write the complete factorization of the polynomial: \[ y = (x - 1)(x - 3)(x + 1) \] ### Step 5: Find the roots To find the x-intercepts (roots), we set each factor equal to zero: 1. \( x - 1 = 0 \) gives \( x = 1 \) 2. \( x - 3 = 0 \) gives \( x = 3 \) 3. \( x + 1 = 0 \) gives \( x = -1 \) ### Conclusion The roots of the polynomial are \( x = 1, x = 3, \) and \( x = -1 \). Therefore, the graph of the function intersects the x-axis **three times**. ### Final Answer The graph of \( y = x^3 - 3x^2 - x + 3 \) intersects the x-axis **3 times**. ---
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