माना `A = [(1,2),(0,1)]`, `A^(n)` = ?

If A= {:[(1,2),(0,1)]:} then A^(n) is

Let A = [[1,2],[0,1]] . Then A^(n) =

If A=[(2,-1),( 3,-2)] , then A^n= [(1, 0),( 0,1)] , if (a) n is an even natural number (b) [(1 ,0),( 0, 1)] , if n is an odd natural number (c) [(1 ,0),( 0, 1)] , if n in N (d) none of these

If A=[(1,2),(0,1)], then A^n= (A) [(1,2n),(0,1)] (B) [(2,n),(0,1)] (C) [(1,2n),(0,-1)] (D) [(1,n),(0,1)]

If A=[(1,2),(0,1)], then A^n= (A) [(1,2n),(0,1)] (B) [(2,n),(0,1)] (C) [(1,2n),(0,-1)] (D) [(1,n),(0,1)]

Let {:[(1,2),(0,1):}][{:(1,2),(0,1):}]......[{:(1,n-1),(0,1):}]=[{:(1,78),(0,1):}] If A=[{:(1,n),(0,1):}] then A^(-1)=

If A=[(1,a),(0, 1)] , then A^n (where n in N) equals [(1,n a),(0, 1)] (b) [(1,n^2a),(0, 1)] (c) [(1,n a),(0 ,0)] (d) [(n,n a),(0,n)]

If A=[(1,a),(0, 1)] , then A^n (where n in N) equals (a) [(1,n a),(0, 1)] (b) [(1,n^2a),(0, 1)] (c) [(1,n a),(0 ,0)] (d) [(n,n a),(0,n)]

If A= [(1,0),(1,1)] then (A) A^-n=[(1,0),(-n,1)] , n epsilon N (B) lim_(n rarr 00)1/n^2 A^-n = [(0,0),(0,0)] (C) lim_(nrarroo)1/n A^-n = [(0,0),(-1,0)] (D) none of these