`3- (2^3 - 2[3 - 16 -: 2]) = `

Let's resolve into factors: (p^2 - 3q^2)^2 - 16 (p^2 - 3q^2) + 63

The sum of the series 1^3/1 + (1^3 + 2^3) / (1 +2) + (1^3 + 2^3 + 3^3) / (1 + 2 + 3) + …… 16 terms is

If 2a - (1)/(2a) = 3, then 16 a ^(4) + (1)/(16 a ^(4)) is equal to

If (x-8)^3+(2x+16)^3+(2x-13)^3= 3 [(x - 8) (2x +16) (2x -13)] , then what is the value of x? यदि (x-8)^3+(2x+16)^3+(2x-13)^3= 3 [(x - 8) (2x +16) (2x -13)] है, तो x का मान ज्ञात करें |

If (3)^2 @ 1 * 7 = 98 and (4)^2 @ 2 * 16 = 178, then (5)^2 @ 3 * 9=?

[(?)^2 + (16)^2 ) + 125 = 3.2

(2)/(3) of 16