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` 1 + cot theta = "cosec" theta`

(b) cosec theta=1+cot theta

(b) cosec theta=1+cot theta

(cosec theta - cot theta) =…………

Prove that: ("cosec" theta + cot theta)/("cosec" theta - cot theta) = ("cosec" theta + cot theta )^(2) = 1 + 2 cot^(2) theta + 2 "cosec" theta cot theta .

( 1 + tan theta + sec theta ) ( 1 + cot theta - cosec theta ) =

Eliminate theta, if x = 3 cosec theta + 4 cot theta, y = 4 cosec theta - 3 cot theta .

(cot theta + "cosec" theta -1)/( cot theta - "cosec" theta +1) is

(cot theta + " cosec " theta -1)/(cot theta - " cosec " theta +1) =

Prove that (cot theta + "cosec" theta -1 )/(cot theta - "cosec" theta +1)=(1+ cos theta)/(sin theta).

Prove that (cot theta + "cosec" theta -1 )/(cot theta - "cosec" theta +1)=(1+ cos theta)/(sin theta).