In an alternating circuit applied voltage is `200V`, if `R=8W X_(L)=X_(C)=6Omega` then write the value of the following
(a)Root mean square value of voltage
(b)Impedance of circuit.

An alternating voltage is given by: e = e_(1) sin omega t + e_(2) cos omega t . Then the root mean square value of voltage is given by:

An alternating voltage is given by: e = e_(1) sin omega t + e_(2) cos omega t . Then the root mean square value of voltage is given by:

An alternating voltage is given by: e = e_(1) sin omega t + e_(2) cos omega t . Then the root mean square value of voltage is given by:

In a series L-C circuit, the applied voltage is V_0. if omega is very low, then the voltage drop across the inductor V_L and capacitor V_C are .

In a series L-C circuit, the applied voltage is V_0. if omega is very low, then the voltage drop across the inductor V_L and capacitor V_C are .

In an L-C-R series circuit R = 10Omega, X_(L) = 8Omega and X_(C) = 6Omega the total impedance of the circuit is -

In an L-C-R series circuit R = 10Omega, X_(L) = 8Omega and X_(C) = 6Omega the total impedance of the circuit is -

In a series L-C-R circuit, currenrt in the circuit is 11A when the applied voltage is 220 V . voltage across the caspcitor is 200 V . If the value of resistor is 20 Omega , then the voltage across the unknown inductor is

In a series L-C-R circuit, currenrt in the circuit is 11A when the applied voltage is 220 V . voltage across the caspcitor is 200 V . If the value of resistor is 20 Omega , then the voltage across the unknown inductor is