A heterozygous individual `++ab` is crossed to its revessive parent and has produced the offsprings in the following proportion.
`++//ab-200`
`a+//ab-50`
`+b//ab-30`
`ab//ab-100`
What is the expected distance between the two gene loci ?

A test cross of F_(1) flies +a/+b produced the following offspring ++/ab=9 ab//ab=9 +b//ab=41 a+//ab=41 What will be distance between linked gene :-

a:b and c:d are in proportion then

What will be the genotypes of parents if they produce offspring with all the four blood groups A, B, AB and O ?

An individual homozygous for gene a and b is cross with wild type and F_1 was back crossed with the double recessive. The appearance of the offspring is as follows ++ to 39 ab to 31 a+ to 17 +b to 13 Find out the distance between genes a and b .

An individual homozygous for gene a and b is cross with wild type and F_1 was back crossed with the double recessive. The appearance of the offspring is as follows ++ to 39 ab to 31 a+ to 17 +b to 13 Find out the distance between genes a and b .

Cross between parents of blood group AB and O will result the offspring having blood groups

Individuals homozygous for ab genes were crossed with wild type (++). The F_(1) hybrid thus produced was test crossed. It produces progeny in following proportion. Now, calculate the distance between a and b genes.

Individuals homozygous for ab genes were crossed with wild type (++). The F_(1) hybrid thus produced was test crossed. It produces progeny in following proportion. Now, calculate the distance between a and b genes.

The percentage of ab gametes produced by AaBb parent will be

Simplify in following. 6a - 2b - ab - (3a+ b - ab) + 2ab - b + a