A body of mass `m` is projected from ground for horizontal range `R`. At the highest point it is fragmented into two identical parts. If one parts returns back to the point of projection, then other part will have the horizontal range

A body is projected from the ground for horizontal range 100m.At the highest point of its parh it breaks apart into two identical part P and Q .If P comes to rest then the horizontal distance of the landing point of part Q, from the point of projection is

A body of mass m is projected at an angle g to the horizontal, the projectile at the highest point breaks into two fragments of equal masses. One of the fragments retraces its path to the point of projection. The velocity of the other fragment just after explosion is

Show that there are two angles of projections for a projectile to have same horizontal range.

A particle is projected such that its horizontal range would be R. At the highest point, the particle breaks into two identical parts P and Q. If P comes to rest, the horizontal distance of point from the point of projection (i.e. origin) where the particle Q lands on the ground is

A projectile of mass 5m is projected at 40m/s at 75^(@) above horizontal It explodes at highest point into two fragments The smaller part of mass m falls at the point of projection.Where does the other part fall? (distance from point of projection) (A) 60m (B) 40m (C) 100m (D) 80m

A projectile of mass 5m is projected at 40m/s at 75^(@) above horizontal It explodes at highest point into two fragments The smaller part of mass m falls at the point of projection.Where does the other part fall? (distance from point of projection) (A) 60m (B)40m (C)100 (D)80

A body is thrown from ground for horizontal range 100 m. If the body breaks into two fragments of mass in the ratio 1 : 2 at the highest point and smaller mass stops there and comes vertically downward, then horizontal range of the centre of mass of the body is