The length of a wire is `1.0 m` and the area of cross-section is `1.0 xx 10^(-2) cm^(2)`. If the work done for increase in length by `0.2 cm` is 0.4 joule, then Young's modulus of the material of the wire is

The Young's modulus of a wire of length 2m and area of cross section 1 mm^(2) is 2 xx 10^(11) N//m^(2) . The work done in increasing its length by 2mm is

The young's modulus of a wire of length 2m and area of cross section 1mm^2 is 2 xx 10^10 N/m^2 . What is the work done in increasing it's length by 2mm.

A wire of length 1m and area of cross section 4 xx 10^(-8) m^(2) increases in length by 0.2 cm when a force of 16 N is applied. Value of Y for the material of the wire will be

A wire of area of cross-section 10^(-6) m^(2) is increased in length by 0.1 %. The tension produced is 1000 N. The Young's modulus of wire is

The area of cross - section of a wire is 1" mm"^(2) and it length is 2 m. How much work will be done to increase its length by 0.1 mm ? The Young.s modulus of elaticity for the material of the wire is 2xx10^(11)" Nm"^(-2) .

The area of cross-section of a wire is 10^(-5) m^2 when its length is increased by 0.1% a tension of 1000N is produced. The Young's modulus of the wire will be

When a wire 2 m long and 0.05 cm^(2) in cross-section is stretched by a mass of 2 kg, it increases in length by 0.04 mm. Young's modulus of the material of the wire is (g=10ms^(-2))

When a wire 2 m long and 0.05 cm^(2) in cross-section is stretched by a mass of 2 kg, it increases in length by 0.04 mm. Young's modulus of the material of the wire is (g=10ms^(-2))

IF the work done in stretching a uniform wire, of cross section 1mm^2 and length 2m, by 1mm is 0.05 joule, find the young's modulus for the material of the wire.