" 16."sqrt(3x^(2)+1)+(4)/(sqrt(3x^(2)+1))=5

Using properties of proportion, solve for x : (i) (sqrt(x + 5) + sqrt(x - 16))/ (sqrt(x + 5) - sqrt(x - 16)) = (7)/(3) (ii) (sqrt(x + 1) + sqrt(x - 1))/ (sqrt(x + 1) - sqrt(x - 1)) = (4x -1)/(2) . (iii) (3x + sqrt(9x^(2) -5))/(3x - sqrt(9x^(2) -5)) = 5 .

Evaluate underset( x rarr oo )("lim") ( sqrt( 3x^(2) - 1) - sqrt( 2x ^(2) - 1))/( 4x + 3)

lim_(x=oo)(sqrt(x^(2)+1)-3sqrt(x^(2)+1))/(4sqrt(x^(4)+1)-5sqrt(x^(4)-1)) is equal to

If (2+sqrt(3))^(x^(2)-1)+(2-sqrt(3))^(x^(2)-1)=4 then x= ?

int(2x+5)/(sqrt(x^(2)+3x+1))

Differentiable the following w.r.t. x : sqrt(3x+2)+1/(sqrt(2x^(2)+4))

Solution of (2+sqrt(3))^(x^(2)-2x+1)+(2-sqrt(3))^(x^(2)-2x-1)=(4)/(2-sqrt(3))are(A)1+-sqrt(3),1(B)1+-sqrt(2),1(C)1+-sqrt(3),2(D)1+-sqrt(2),2

Rationalise the denominator: (a) (1)/(root(3)(3) + root(3)(2)) , (b) (2)/(sqrt5 + sqrt3 + sqrt2) , (c) (x^(2))/(sqrt(x^(2) + y^(2)) - y) , (d) (1)/(sqrt6 + sqrt5 - sqrt11) (e) (sqrt(x + 2y) - sqrt(x -2y))/(sqrt(x + 2y) + sqrt(x - 2y)) , (f) (sqrt10 + sqrt5 - sqrt3)/(sqrt10 - sqrt5 + sqrt3)

lim_ (x rarr oo) (sqrt (3x ^ (2) +1) -sqrt (2x ^ (2) -3x + 5)) / (7x + 2) =