The mean and standard deviation of `20` items are found to be `10` and `2` respectively. At the time of checking it was found that an item `12 ` was wrongly entered as `8`. Calcualte the correct mean and standard deviation.

The mean and the standard deviation of a group of 20 items was tound to be 40 and 15 respectively. While checking it was found that an item 43 was wrongly written as 53 Calculate the correct mean and standard deviation.

For a group of 100 candidatges the mean and standard deviation of their marks were found to be 60 and 15 respectively. Later on it was found that the scores 45 and 72 were wrongly entered as 40 and 27. Find the correct means and standard deviation.

The mean and standard deviation of 20 observations are found to be 10 and 2, respectively. On rechecking, it was found that an observation 8 was incorrect. Calculate the correct mean and standard deviation in each of the following cases: (i) If wrong item is omitted. (ii) If it is replaced by 12.

The mean and standard deviation of 15 observations are found to be 10 and 5 respectively. On reachecking it was found that one of the observation with value 8 was incorrect. Calculate the correct mean and standard deviation if the correct observation value was 23 ?

The mean and standard deviation of 10 observations are found to be 10 and 4 respectively. Later it was found that one item is mistaken as 10 instead of 12. Find the correct mean and standard deviation.

If the mean and standard deviation of a data are 8 and 2 respectively then the co-efficient of variation is ___.

Find the mean and standard deviation for the following data.

Mean and standard deviation of a data are 48 and 12 respectively. The coefficient of variation is .............

If the mean and standard deviation of a binomial distribution are 12 and 2 respectively . Then the value of its parameter p is ………….. .