Let `A_(n)` be the area enclosed by the `n^(th)` orbit in a hydrogen atom. The graph of `l n (A_(n)//A_(t))` against In `(n)`

Let A_(0) be the area enclined by the orbit in a hydrogen atom .The graph of in (A_(0) //A_(1)) againest in(pi)

The figure shows a graph between 1n |(A_(n))/(A_(1))| and 1n|n| , where A_(n) is the area enclosed by the n^(th) orbit in a hydrogen like atom. The correct curve is

In hydrogen atom, the area enclosed by n^(th) orbit is A_(n) . The graph between log (A_(n)/A_(1)) log will be

The magnitude of acceleration of the electron in the n^(th) orbit of hydrogen atom is a_(H) and that of singly ionized helium atom is a_(He) . The ratio a_(H):a_(He) is

If, in a hydrogen atom, radius of nth Bohr orbit is r_(n) frequency of revolution of electron in nth orbit is f_(n) and area enclosed by the nth orbit is A_(n) , then which of the pollowing graphs are correct?

If A_(n) is the area bounded by y=x and y=x^(n), n in N, then A_(2).A_(3)…A_(n)=

For a H-like species if area A_(1) is of ground state orbit and area A_(n) is of nth orbit, then, the plot of (A_(n))/(A_(1)) us n^(2) looks like:

Let A_(1), A_(2), A_(3),….., A_(n) be squares such that for each n ge 1 the length of a side of A _(n) equals the length of a diagonal of A _(n+1). If the side of A_(1) be 20 units then the smallest value of 'n' for wheich area of A_(n) is less than 1.

Let A_(1), A_(2), A_(3), ........ be squares such that for each n ge 1 , the length of the side of A_(n) equals the length of diagonal of A_(n+1) . If the length of A_(1) is 12 cm, then the smallest value of n for which area of A_(n) is less than one, is ______.