A particle moves along a line by `s=t^(3)-9t^(2)+24t` then S is decreasing when` t in`

The equation of motion of a particle moving along a straight line is s=2t^(3)-9t^(2)+12t , where the units of s and t are centrimetre and second. The acceleration of the particle will be zero after

A particle moves according to law s=t^(3)-6t^(2)+9t+15 . Find the velocity when t = 0.

A particle moves along the X-axis as x=u(t-2s)=at(t-2)^2 .

A particle moves according to the law x=t^(3)-6t^(2)+9t+5 . The displacement of the particle at the time when its acceleration is zero, is

A particle is moving along the x-axis such that s=6t-t^(2) , where s in meters and t is in second. Find the displacement and distance traveled by the particle during time interval t=0 to t=5 s .

The speed(v) of a particle moving along a straight line is given by v=(t^(2)+3t-4 where v is in m/s and t in seconds. Find time t at which the particle will momentarily come to rest.

A particle is moving such that s=t^(3)-6t^(2)+18t+9 , where s is in meters and t is in meters and t is in seconds. Find the minimum velocity attained by the particle.

A particle moves along x-axis according to the law x=(t^(3)-3t^(2)-9t+5)m . Then :-

The displacement of a particle moving along an x axis is given by x=18t+5.0t^(2) , where x is in meters and t is in seconds. Calculate (a) the instantaneous velocity at t=2.0s and (b) the average velocity between t=2.0s and t=3.0s .