Spin only magnetic moment of a compound showing paramagnetism is nearly `54.865times10^(-24)Am^(2)` Bohr magneton.How many unpaired electrons are there in the compound? `(9.27times10^(-24)Am^(2)=1 mu_(B))`

Spin only magnetic moment of a compound showing paramagnetism is nearly."54.865*10^(-24) Am^(2) Bohr magneton.How many unpaired electrons are there in the compound?

A compound of a metal ion M^(X+)(z=24) has a spin only magnetic moment of sqrt(15)B.M. . The number of unpaired electrons in the compound are

The magnetic moment of ion is close to 36 xx 10^(-24) "joule"//"Tesla" . The number of unpaired electrons of the ions are

A compound has been found to have magnetic moment of 3.9 B.M. How many unpaired electrons does it contain ?

Transition metals and many of their compounds show paramagnetic behaviour where there are unpaired electron or electrons. The magnetic moment arises from the spin and orbital motions in ions or molecule. Magnetic moment of n unpaired electrons is given as mu=sqrt(n(n+2)) Bohr magneton Magnetic moment increases as the number of unpaired electrons increases. Q. Which among the following ions has maximum value of magnetic moment

Transition metals and many of their compounds show paramagnetic behaviour where there are unpaired electron or electrons. The magnetic moment arises from the spin and orbital motions in ions or molecule. Magnetic moment of n unpaired electrons is given as mu=sqrt(n(n+2)) Bohr magneton Magnetic moment increases as the number of unpaired electrons increases. Q. In 3d series the maximum magnetic moment is shown by

Transition metals and many of their compounds show paramagnetic behaviour where there are unpaired electron or electrons. The magnetic moment arises from the spin and orbital motions in ions or molecule. Magnetic moment of n unpaired electrons is given as mu=sqrt(n(n+2)) Bohr magneton Magnetic moment increases as the number of unpaired electrons increases. Q. There are three unpaired electrons in [Co(H_2O)_6]^(2+) and calculated value of magnetic moment on the basis of sqrt(n(n+2)) formula is 3.87 BM. which is lower than the expermental value of 4.40 BM. The reason for this difference is due to

Transition metals and many of their compounds show paramagnetic behaviour where there are unpaired electron or electrons. The magnetic moment arises from the spin and orbital motions in ions or molecule. Magnetic moment of n unpaired electrons is given as mu=sqrt(n(n+2)) Bohr magneton Magnetic moment increases as the number of unpaired electrons increases. Q. Magnetic moments of Cr(Z=24),Mn^(o+)(Z=35) and Fe^(2+)(Z=36) are x,y and z respectively. Which of the following order is correct?

Transition metals and many of their compounds show paramagnetic behaviour where there are unpaired electron or electrons. The magnetic moment arises from the spin and orbital motions in ions or molecule. Magnetic moment of n unpaired electrons is given as mu=sqrt(n(n+2)) Bohr magneton Magnetic moment increases as the number of unpaired electrons increases. Q. Magnetic moment of [Ni(CN)_4]^(2-) is zero but that of [Ni(H_2O)_4]^(2+) is 2.83BM . is because of :

Transition metals and many of their compounds show paramagnetic behaviour where there are unpaired electron or electrons. The magnetic moment arises from the spin and orbital motions in ions or molecule. Magnetic moment of n unpaired electrons is given as mu=sqrt(n(n+2)) Bohr magneton Magnetic moment increases as the number of unpaired electrons increases. Q. Increasing value of magnetic moment of (I) [Fe(CN)_6]^(4-) (II) [Fe(CN)_6]^(3-) , (III) [Cr(NH_3)_6]^(3+) (IV) [Ni(H_2O)_4]^(2+) is: