When a body is placed on a rough plane inclined at an angle `theta` to the horizontal, its acceleration is

A block of mass m is placed on a rough plane inclined at an angle theta with the horizontal. The coefficient of friction between the block and inclined plane is mu . If theta lt tan^(-1) (mu) , then net contact force exerted by the plane on the block is :

A block of mass m is placed on a rough plane inclined at an angle theta with the horizontal. The coefficient of friction between the block and inclined plane is mu . If theta lt tan^(-1) (mu) , then net contact force exerted by the plane on the block is :

A block is placed on a smooth inclined plane at an angle 'theta' to the horizontal. The acceleration must the plane be moved horizontally so that the block to fall freely is

A body just slides a rough plane inclined at an angle of 30^(@) with the horizontal. Calculate the acceleration with which the body will slide down when the inclination in the plane is changed to 45^(@) . Take g=9.8ms^(-2)

A body slides down on a rough inclined surface making an angle of 60^@ with the horizontal. Find its acceleration if mu=0.2 .