Force between two identical charges placed at a distance of `r` in vacume is `F`. Now a slab of dielectric constant 4 is inserted between these two charges . If the thickness of the slab is `r//2`, then the force between the charges will becomes

Force between two charges separated by a distance r varies as r^(2) ?

If a dielectric is placed between two charges in place of vacuum or air, then the force between the charges will

Two charges are placed in vacuum at a distance d apart. The force between them is F. if a medium of dielectric constant 2 is introduced between them, the force will now be

The force between two charges in free space is F. If a dielectric medium of dielectric constant K is placed the force between two charges is…………

One brass plate is inserted between two charges. The force between two charges will be

The force of repulsion between two identical positive charges when kept with aseparation r in air is F. half the gap between the two charges is filled by a dielectric slab of dielectric constant = 4. thenthe new force of repulsion between those two charges becomes

Two similar point charges q_1 and q_2 are placed at a distance r apart in the air. The force between them is F_1 . A dielectric slab of thickness t(ltr) and dielectric constant K is placed between the charges . Then the force between the same charge . Then the fore between the same charges is F_2 . The ratio is