If c is negative then the distance of the straight line `ax+by+c=0` from the origin is -

The distance of the straight line a(x-a)+b(y-b)=0 from the origin is -

A circle passes through the point (3,4) and cuts the circle x^(2)+y^(2)=c^(2) orthogonally,the locus of its centre is a straight line.If the distance of this straight line from the origin is 25. then a^(2)=

The perpendicular distance of the straight line 3x + 4y + 15 = 0 from the origin, is

A straight line passing through P(3,1) meets the coordinate axes at Aa n dB . It is given that the distance of this straight line from the origin O is maximum. The area of triangle O A B is equal to

A straight line passing through P(3,1) meets the coordinate axes at Aa n dB . It is given that the distance of this straight line from the origin O is maximum. The area of triangle O A B is equal to

A circle passes through the point (3, 4) and cuts the circle x^2+y^2=c^2 orthogonally, the locus of its centre is a straight line. If the distance of this straight line from the origin is 25. then a^2=

The condition for which the straight line ax +by +c=0 will pass throught the origin is -

A straight line passes through the point (3,5) and is such that the portion of it intercepted between the axes is bisected at the point . Find the equation of the straight line and also its distance from the origin.