If `vec(F)=yhati+xhatj` then find out the work done in moving the particle from position (2, 3) to (5, 6)

If vec(F) = y hat(i) + x hat(j) then find out the work done in moving the particle from position (2,3) to (5,6)

The work done by the force F=2i-3j+2k in moving a particle from (3,4,5) to (1,2,3) is

A force F=(3xhati+4hatj) Newton (where x is in metres) acts on a particle which moves from a position (2m, 3m) to (3m, 0m). Then the work done is

The work done by the force F = 2i - 3j + 2k in moving a particle from (3,4,5) to (1,2,3) is

Calculate the work done to displace the particle from (1,2) to (4,5). If vec(F) = 4hat(i) + 3hat(j)

A force F acting on a particle varies with the position x as shown in the graph. Find the work done by the force in displacing the particle from x =-a to x = +2a . .

What will be work done by a force vec(F) = 2hat(i) +2hat(j) - 4hat(k) when it moves a body from the point (2,0,-3) to (1,1,-5)