[" a colloidal sol."],[" conductivity.The conductivity of "0.001028" mol "L^(-1)" acetic acid is "4.95times],[" te its dissociation constant if limiting molar conductivity for acetic acid "]

The conductivity of 0.001028 mol L^(-1) acetic acid is 4.95 xx 10^-5 S cm^-1 . Calculate its dissociation constant if A_m^@ for acetic acid is 390.5 S cm^2 mol^(-1).

The conductivity of 0.001028 mol L^-1 acetic acid is 4.95 xx 10^-5 Scm^-1 , Calcụlate its dissociation constint if Lambda_m^0 for acetic acid is 390.5 Scm^2 mol :

The conductivity of 0.001028 mol L ^(-1) acetic acid is 4.95 xx10^(-5)S cm ^(-1). Calculate its dissociation constant if ^^(m)^(0) for acetic acid id 390.5 S cm ^(2)mol ^(-1).

The conductivity of "0.001028 mol.L"^(-1) acetic acid is 4.95xx10^(-5)"S.cm"^(-1) . Calculate its dissociation constant if Lambda_(m)^(@) for acetic acid is "390.5 S.cm"^(2)."mol"^(-1) .

The conductivity of 0.001028 mol L^(-1) acetic acid is 4.95 xx 10^(-5) S cm^(-1) . Calculate its dissociation constant if Lambda_(m)^(0) for acetic is 390.5 S cm^(2) mol^(-1) ?

The conductivity of 0.001028M acetic acid is 4.95xx10^(-5)Scm^(-1) . Calculate its dissociation constant if Lambda_(m)^(0) for acetic acid is 390.5Scm^(2)mol^(-1) .

Calculating the value of dissociation constant of weak electrolyte: The conductivity of 0.001028 mo L^(-1) acetic acid is 4.95 xx 10^(-5) S cm^(-1) . Calculate its dssociation constatnt if Lambda_(m)^(0) for acetic acid is 390.5 S cm^(2) mol^(-1) . Strategy: We can determine the value of the dissociation constant for week electrolytes once we know the Lambda_(m)^(0) and Lambda_(m) at any given concentration C .

The conductivity of 0.001 M acetic is 4 xx 10^(-5)S//cm. Calculate the dissociation constant of acetic acid, if molar conductivity at infinite dilution for acetic is 390 S cm^(2)//mol.