(dy)/(dx)+2y tan x=sin x

The differential equations,find a particular solution satisfying the given condition: (dx)/(dy)+2y tan x=sin x;y=0 when x=(pi)/(3)

If (dy)/(dx)+y tan x=sin2x and y(0)=1, then y(pi) is equal to:

If (dy)/(dx)+y tan x=sin2x and y(0)=1 , then y(pi) is equal to :

(dy)/(dx) + 2 y tan x = sin x

(dy)/(dx) + 2 y tan x = sin x, y = 0 when x = (pi)/(3) .

If y=yır) is the solution of the differential equation, (dy)/(dx) + 2 y tan x = sin x, y ((pi)/(3))= 0, then the maximum value of the function y(x) over R is equal to :

Solutions of the differential equations (dy)/(dx) tan y= sin (x+y) +sin (x-y) is

(dy) / (dx) tan y = sin (x + y) + sin (xy)