If ` P = (tan(3^(n+1)theta - tantheta)`

tan 3theta = tan 2theta + tantheta

Solve: tan^(3)theta-3tantheta=0

Solve: tan^(3)theta-3tantheta=0

tantheta=? tan(90-theta)=?

Solve: tan3theta+tantheta=0

Solve: tan3theta+tantheta=0

If: tantheta + tan 2theta + tan 3theta = tan theta.tan2theta.tan 3theta , then: theta =

If tantheta - tan^(2) theta = 1 , then tan^(4) theta-2tan^3theta-tan^2theta+2tantheta+1 has value 4.

Prove that: sectheta sec 2theta+sec2thetasec3theta+sec3theta.sec4theta+…to n terms = 1/(sintheta) [tan(n+1)theta-tantheta]