`cos(alpha+beta)+sin(alpha-beta)=0"and"tanbeta=1/2009`

If cos(alpha+beta)+sin(alpha-beta)=0 and 2010tanbeta+1=0 then tan alpha is equal to

If cos( alpha+beta) + sin(alpha-beta) = 0 and 2010tan beta - 1 = 0 then tan alpha is equal to

If cos( alpha+beta) + sin(alpha-beta) = 0 and 2010tan beta + 1 = 0 then tan alpha is equal to

Find the value of f(alpha, beta) =|(cos (alpha + beta), -sin (alpha + beta), cos 2beta),(sin alpha, cos alpha, sin beta),(-cos alpha, sin alpha, cos beta)|

(i) sin (alpha + beta) = sin alpha cos beta + cos alpha sin beta) (ii) sin (alpha-beta)= sin alpha cos beta- cos alpha sin beta Proof

If cos alpha+cos beta=0=sin alpha+sin beta, then cos2 alpha+cos2 beta is equal to (a)-2sin(alpha+beta)(b)-2cos(alpha+beta)(c)2sin(alpha+beta)(d)2cos(alpha+beta)

The value of the determinant Delta = |(cos (alpha + beta),- sin (alpha + beta),cos 2 beta),(sin alpha,cos alpha,sin beta),(- cos alpha,sin alpha,- cos beta)| , is

The value of the determinant Delta = |(cos (alpha + beta),- sin (alpha + beta),cos 2 beta),(sin alpha,cos alpha,sin beta),(- cos alpha,sin alpha,- cos beta)| , is

If tanalpha and tanbeta be the roots of the equation (x^2+px+q=0) then the value of the expression sin^2(alpha+beta)+p sin(alpha+beta)cos(alpha+beta)+qcos^2(alpha+beta) is

If cot(alpha+beta)=0, then sin(alpha+2 beta) can be (a)-sin alpha(b)sin beta(c)cos alpha(d)cos beta