`x_(1)=A sin (omegat-0.1x)` and `x_(2)=A sin (omegat-0.1 x-(phi)/2)` Resultant amplitude of combined wave is

If two waves x_1 =A sin (omegat -0.1 x ) and x_2 A sin (omegat -0.1x -phi //2 ) are combined with each other ,then resultant amplitude of the combined waves is

If two waves x_1 =A sin (omegat -0.1 x ) and x_2 A sin (omegat -0.1x -phi //2 ) are combined with each other ,then resultant amplitude of the combined waves is

A particle is subjected to two SHMs x_(1) = A_(1) sin omegat and x_(2) = A_(2)sin (omegat +(pi)/(4)) . The resultant SHM will have an amplitude of

A particle is subjected to SHM as given by equations x_1 = A_1 sin omegat and x_2 = A_2 sin (omega t + pi//3) .The maximum acceleration and amplitude of the resultant motion are it a_("max") and A ,respectively , then

two waves y_1 = 10sin(omegat - Kx) m and y_2 = 5sin(omegat - Kx + π/3) m are superimposed. the amplitude of resultant wave is

two waves y_1 = 10sin(omegat - Kx) m and y_2 = 5sin(omegat - Kx + π/3) m are superimposed. the amplitude of resultant wave is

Equations of two progressive wave are given by y_(1) = asin (omega t + phi_(1)) and y_(2) = a sin (omegat + phi_(2)) . IF amplitude and time period of resultant wave is same as that of both the waves, then (phi_(1)-phi_(2)) is