A solution curve of the differential equation `(x^2+xy+4x+2y+4)((dy)/(dx))-y^2=0` passes through the point `(1,3)` Then the solution curve is

A solution curve of the differential equation (x^(2)+xy+4x+2y+4)(dy)/(dx)-y^(2)=0, x gt0 , passes through the point (1, 3). Then the solution curve-

The solution curve of the differential equation, (1+e^(-x))(1+y^(2))(dy)/(dx)=y^(2) , which passes through the point (0,1), is:

The solution of the differential equation (2x-4y+3)(dy)/(dx)+(x-2y+1)=0 is

The solution of the differential equation (2x-4y+3)(dy)/(dx)+(x-2y+1)=0 is

The solution of the differential equation (2x-4y+3) (dy)/(dx)+(x-2y+1)=0 is

The solution of the differential equation (xy^4 + y) dx-x dy = 0, is

The solution of the differential equation (xy^4 + y) dx-x dy = 0, is

The solution of the differential equation (xy^4 + y) dx-x dy = 0, is

The solution of the differential equation (xy^4 + y) dx-x dy = 0, is

The solution of the differential equation (2x^(2) +2 y^(2))dx- 4xy dy= 0 is