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(ax^(2)+b)^(2)...

(ax^(2)+b)^(2)

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The roots of the equation x^(2)+2ax+a^(2)+b^(2)=0 are

The roots of the equation x^(2)+2ax+a^(2)+b^(2)=0 are

{:(x + y = a + b),(ax - by = a^(2) - b^(2)):}

{:(ax - by = a^(2) + b^(2)),(x + y = 2a):}

{:(ax - by = a^(2) + b^(2)),(x + y = 2a):}

36x^(2)-12ax+(a^(2)-b^(2))=0

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The curves ax^(2)+by^(2)=1 and Ax^(2)+B y^(2) =1 intersect orthogonally, then