tan^(-1)a/x

If tan^(-1)(x-1)+tan^(-1)x+tan^(-1)(x+1)=tan^(-1)3x , then x =

Let |{:(tan^(-1)x, tan^(-1)2x, tan^(-1)3x), (tan^(-1)3x, tan^(-1)x, tan^(-1)2x), (tan^(-1)2x, tan^(-1)3x, tan^(-1)x):}|=0 , then the number of values of x satisfying the equation is

Solve : tan^(-1)(x-1)+tan^(-1)x+tan^(-1)(x+1)=tan^(-1)3x

Solve: tan^(-1)(x-1)+tan^(-1)x+tan^(-1)(x+1)= tan^(-1)3x.

Solve tan^(-1)(x-1) +tan^(-1) x +tan^(-1)(x+1)= tan^(-1)(3x) .

Solve : tan^(-1)(x-1)+tan^(-1)x+tan^(-1)(x+1)=tan^(-1)3x

tan^(-1)x+tan^(-1) (1-x) = 2 tan ^(-1) sqrt(x(1-x))

(d)/(dx)[tan{tan^(-1)((x)/(a))-tan^(-1)((x-a)/(x+a))}]=

d/dx [tan (tan^(-1) (x/a) - tan^(-1) ((x-a)/(x+a)))] =