If `x=111........1(20 digits ) y=333........3(10 digits) z=222..........2(10 digits)` then `x-z` is

If x=111.....(20 digits),y=33......(10digits) and z=222.....(10 digits), then (x-y^(2))/(z) equals.

If x=111"...."(20 digits),y=333"...."(10digits) and z=222".....2"(10 digits), then (x-y^(2))/(z) equals.

If x=111"...."(20 digits),y=333"...."(10digits) and z=222".....2"(10 digits), then (x-y^(2))/(z) equals.

If x=111"...."(20 digits),y=333"...."(10digits) and z=222".....2"(10 digits), then (x-y^(2))/(z) equals.

If x = 111 ……….. 1 (20 digits), y = 333….3 (10 digits) and z = 222…. 2 (10 digits), then what is (x − y^2) / (z) equal to ?

If x = 1111..... 20 times, y = 333 ......... 10 times, z = 2222 ....... 10 times. Find the value of (x-y^(2))/(z)

The number of 10 digit numbers formed by using the digits 1&2 is

In a 2 digit number, the units place digit is x. If the sum of digits be 9, then the number is (10x – 9).

If x + y + z = 6 and z is an odd digit, then the three-digit number xyz is