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[" The algebraic sum of distances of the...

[" The algebraic sum of distances of the line "ax+by+2=0" from "(1,2),(2,1)" and "],[(3,5)" is zero and the lines "bx-ay+4=0" and "3x+4y+5=0" cut the co-ordinate "],[" axes at concyclic points then "]

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The algebraic sum of distances of the line ax + by + 2 = 0 from (1,2), (2,1) and (3,5) is zero and the lines bx - ay + 4 = 0 and 3x + 4y + 5=0 cut the coordinate axes at concyclic points. Then (a) a+b=-2/7 (b) area of triangle formed by the line ax+by+2=0 with coordinate axes is 14/5 (c) line ax+by+3=0 always passes through the point (-1,1) (d) max {a,b}=5/7

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